The filament of a light bulb has surface area 64 mm
2
. The filament can be considered as a black
body at temperature 2500 K emitting radiation like a point source when viewed from far. At night
the light bulb is observed from a distance of 100 m. Assume the pupil of the eyes of the observer to
be circular with radius 3 mm. Then
(Take Stefan-Boltzmann constant = 5.67 \times 10
−8
Wm
−2
K
−4
, Wien’s displacement constant =
2.90 \times 10
−3
m-K, Planck’s constant = 6.63 \times 10
−34
Js, speed of light in vacuum = 3.00 \times
10
8
ms
−1
)