Question 665: Thermodynamics & KTG

Question

When the heat is given to a gas in an Isothermal process, then there will be

Accepted Answer

In an
isothermal process
, the temperature of the gas
remains constant
.
By definition, $\Delta T = 0$ (no change in temperature).
According to the first law of thermodynamics:
$$ \Delta Q = \Delta U + W $$
Where:
$\Delta Q$ = Heat supplied to the system
$\Delta U$ = Change in internal energy
$W$ = Work done by the system
In an isothermal process for an ideal gas:
$\Delta U = 0$ (since internal energy depends only on temperature, and temperature is constant)
So, all the heat supplied ($\Delta Q$) is converted into work done ($W$):
$$   \Delta Q = W   $$
Analysis of Options:
Option A:
external work done Ã¢ÂÂ Correct, as heat supplied is used to do work.
Option B:
rise in temperature Ã¢ÂÂ Incorrect, temperature remains constant.
Option C:
increase in internal energy Ã¢ÂÂ Incorrect, internal energy does not change.
Option D:
external work done and also rise in temperature Ã¢ÂÂ Incorrect, no rise in temperature.
Final Answer:
Option A: external work done.

Answer

external work done.

Answer

rise in temperature.

Answer

increase in internal energy.

Answer

external work done and also rise in temperature.

Thermodynamics & KTG

When the heat is given to a gas in an Isothermal process, then there will be

Choose the correct answer: