Question 483: Thermodynamics & KTG

Question

The temperature-entropy diagram of a reversible engine cycle is given in the figure. Its efficiency is
![](https://imagex.cdn.examgoal.net/1ki9uu6gm/649ecc29-b989-4cbb-b7bf-eb735b79c834/601f8470-35f5-11eb-952a-0b7dd2481a83/file-1ki9uu6gn-320w.png)

Accepted Answer

${Q_1} = {T_0}{S_0} + {1 \over 2}{T_0}{S_0} = {3 \over 2}{T_0}{S_0}$
${Q_2} = {T_0}\left( {2{S_0} - {S_0}} \right)$ $ = {T_0}{S_0}$
and ${Q_3} = 0$
$\eta  = 1 - {{{Q_2}} \over {{Q_1}}} = 1 - {{{T_0}{S_0}} \over {{3 \over 2}{T_0}{S_0}}} = {1 \over 3}$
![](https://imagex.cdn.examgoal.net/kAul6Zipjhs1b83Bp/sgR1ki5caDmEl24gjNmX0pVJkcb0s/M5CynqZyjTfAhzS1hlaaCn/image.svg)

Answer

${1 \over 4}$

Answer

${1 \over 2}$

Answer

${2 \over 3}$

Answer

${1 \over 3}$

Thermodynamics & KTG

The temperature-entropy diagram of a reversible engine cycle is given in the figure. Its efficiency is

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