Question 953: Thermodynamics & KTG

Question

The ratio of the specific heats $${{{C_p}} \over {{C_v}}} = \gamma $$ in terms of degrees of freedom (n) is given by

Accepted Answer

For n degrees of freedom, $${C_v} = {n \over 2}R$$
Also, $${C_p} - {C_v} = R$$
$${C_p} = {C_v} + R = {n \over 2}R + R = \left( {{n \over 2} + 1} ight)R$$
$$\gamma  = {{{C_p}} \over {{C_v}}} = {{\left( {{n \over 2} + 1} ight)R} \over {{n \over 2}R}} = {{n + 2} \over n}$$
$$ 	herefore $$ $$\gamma  = 1 + {2 \over n}$$

Answer

$$\left( {1 + {2 \over n}} \right)$$

Answer

$$\left( {1 + {n \over 2}} \right)$$

Answer

$$\left( {1 + {1 \over n}} \right)$$

Answer

$$\left( {1 + {n \over 3}} \right)$$

Thermodynamics & KTG

The ratio of the specific heats ${{{C_p}} \over {{C_v}}} = \gamma $ in terms of degrees of freedom (n) is given by

Choose the correct answer: