Question 956: Thermodynamics & KTG

Question

A thermodynamic system undergoes cyclic process ABCDA as shown in figure. The work done by the system in the cycle is
![](https://neetcare-image.cdn.examgoal.net/1qpq2yck7l65udl/4caa5b99-6573-4781-a837-1962f78f282a/e6e4f6a0-6267-11ea-bddc-5f310cab17d0/file-1qpq2yck7l65udm-372w.jpg)

Accepted Answer

In a cyclic process work done is equal to the area under the cycle and is positive if the cycle is clockwise and negative if anticlockwise. As is clear from figure,
${W_{AEDA}} =  + area\,of\,\Delta AED =  + {1 \over 2}{P_0}{V_0}$
${W_{BCEB}} =  - area\,of\Delta BCE =  - {1 \over 2}{P_0}{V_0}$
The net work done by the system is
${W_{net}} = {W_{AEDA}} + {W_{BCEB}}$
$ =  + {1 \over 2}{P_0}{V_0} - {1 \over 2}{P_0}{V_0} = 0$
![](https://neetcare-image.cdn.examgoal.net/1qpq2yck7l65udl/4caa5b99-6573-4781-a837-1962f78f282a/e6e4f6a0-6267-11ea-bddc-5f310cab17d0/file-1qpq2yck7l65udm-372w.jpg)

Answer

P
0
V
0

Answer

2P
0
V
0

Answer

${{{P_0}{V_0}} \over 2}$

Answer

zero

Thermodynamics & KTG

A thermodynamic system undergoes cyclic process ABCDA as shown in figure. The work done by the system in the cycle is

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