Question 945: Thermodynamics & KTG

Question

A refrigerator works between 4
o
C and 30
o
C. It is required to remove 600 calories of heat every second in order to keep the temperature of the refrigerated space constant. The power required is (Take 1 cal = 4.2 Joules)

Accepted Answer

Now $$COP = {{{L_Q}} \over {Power}} = {{{T_L}} \over {{T_H} - {T_L}}}$$
$$ \Rightarrow Power = {{{L_Q} 	imes \left( {{T_H} - {T_L}} ight)} \over {{T_L}}}$$
= (600 ÃÂ 4.2) ÃÂ 26/277 = 236.53 W

Answer

236.5 W

Answer

2365 W

Answer

2.365 W

Answer

23.65 W

Thermodynamics & KTG

A refrigerator works between 4 o C and 30 o C. It is required to remove 600 calories of heat every second in order to keep the temperature of the refrigerated space constant. The power required is (Take 1 cal = 4.2 Joules)

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