Question 196: Thermodynamics & KTG

Question

A thermodynamic system is taken from an original state $\mathrm{A}$ to an intermediate state $B$ by a linear process as shown in the figure. It's volume is then reduced to the original value from $\mathrm{B}$ to $\mathrm{C}$ by an isobaric process. The total work done by the gas from $A$ to $B$ and $B$ to $C$ would be :
![](https://app-content.cdn.examgoal.net/fly/@width/image/6y3zli1lsfm6q3u/d652f13e-3bb3-4f30-b8c0-1bb318f67685/322c07b0-c7d2-11ee-a6e7-91ff3070e761/file-6y3zli1lsfm6q3v.png?format=png)

Accepted Answer

Work done $\mathrm{AB}=\frac{1}{2}(8000+4000)$ Dyne$/\mathrm{cm}^2 	imes 4 \mathrm{~m}^3=\left(6000ight.$ Dyne$\left./\mathrm{cm}^2ight) 	imes 4 \mathrm{~m}^3$
Work done $\mathrm{BC}=-\left(4000ight.$ Dyne$\left./\mathrm{cm}^2ight) 	imes 4 \mathrm{~m}^3$
Total work done $=2000$ Dyne$/\mathrm{cm}^2 	imes 4 \mathrm{~m}^3$
$\begin{aligned}
=2 	imes 10^3 & 	imes \frac{1}{10^5} \frac{\mathrm{N}}{\mathrm{cm}^2} 	imes 4 \mathrm{~m}^3 \
& =2 	imes 10^{-2} 	imes \frac{\mathrm{N}}{10^{-4} \mathrm{~m}^2} 	imes 4 \mathrm{~m}^3 \
& =2 	imes 10^2 	imes 4 \mathrm{Nm}=800 \mathrm{~J}
\end{aligned}$
![](https://app-content.cdn.examgoal.net/fly/@width/image/1lt2upqw6/b30c7280-75de-47ab-98e4-e0fd16fc60ca/931f7060-d499-11ee-8574-81dc091f6c89/file-1lt2upqw7.png?format=png)

Answer

800 J

Answer

2200 J

Answer

33800 J

Answer

1200 J

Thermodynamics & KTG

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