Question 920: Thermodynamics & KTG

Question

A Carnot engine has an efficiency of $$50 \%$$ when its source is at a temperature $$327^{\circ} \mathrm{C}$$. The temperature of the sink is :-

Accepted Answer

Efficiency of carnot engine
$$
\begin{aligned}
& \% \eta=\left(1-\frac{T_{	ext {sink }}}{\mathrm{T}_{	ext {source }}}ight) 	imes 100 \
& T_{	ext {source }}=327^{\circ} \mathrm{C}=600 \mathrm{~K} \
& 50=\left(1-\frac{\mathrm{T}_{	ext {sink }}}{600}ight) 	imes 100 \
& \frac{1}{2}=1-\frac{\mathrm{T}_{	ext {sink }}}{600} \
& \mathrm{~T}_{	ext {Sink }}=300 \mathrm{~K}
\end{aligned}
$$
So temp. of sink is $${ }^{\circ} \mathrm{C}=300-2763=27^{\circ} \mathrm{C}$$

Answer

$$15^{\circ} \mathrm{C}$$

Answer

$$100^{\circ} \mathrm{C}$$

Answer

$$200^{\circ} \mathrm{C}$$

Answer

$$27^{\circ} \mathrm{C}$$

Thermodynamics & KTG

A Carnot engine has an efficiency of $50 \% when its source is at a temperature 327^{\circ} \mathrm{C}$. The temperature of the sink is :-

Choose the correct answer: