Question 330: Thermodynamics & KTG

Question

Two ideal polyatomic gases at temperatures T
1
and T
2
are mixed so that there is no loss of energy. If F
1
and F
2
, m
1
and m
2
, n
1
and n
2
be the degrees of freedom, masses, number of molecules of the first and second gas respectively, the temperature of mixture of these two gases is :

Accepted Answer

Initial internal energy = Final internal energy
$${{{F_1}} \over 2}{n_1}R{T_1} + {{{F_2}} \over 2}{n_2}R{T_2} = {{{F_1}} \over 2}{n_1}RT + {{{F_2}} \over 2}{n_2}RT$$
$$ \Rightarrow $$ $$T = {{{F_1}{n_1}{T_1} + {F_2}{n_2}{T_2}} \over {{F_1}{n_1} + {F_2}{n_2}}}$$

Answer

$${{{n_1}{F_1}{T_1} + {n_2}{F_2}{T_2}} \over {{F_1} + {F_2}}}$$

Answer

$${{{n_1}{F_1}{T_1} + {n_2}{F_2}{T_2}} \over {{n_1}{F_1} + {n_2}{F_2}}}$$

Answer

$${{{n_1}{T_1} + {n_2}{T_2}} \over {{n_1} + {n_2}}}$$

Answer

$${{{n_1}{F_1}{T_1} + {n_2}{F_2}{T_2}} \over {{n_1} + {n_2}}}$$

Thermodynamics & KTG

Two ideal polyatomic gases at temperatures T 1 and T 2 are mixed so that there is no loss of energy. If F 1 and F 2 , m 1 and m 2 , n 1 and n 2 be the degrees of freedom, masses, number of molecules of the first and second gas respectively, the temperature of mixture of these two gases is :

Choose the correct answer: