Question 290: Thermodynamics & KTG

Question

The relation between root mean square speed (v
rms
) and most probable sped (v
p
) for the molar mass M of oxygen gas molecule at the temperature of 300 K will be :

Accepted Answer

$${v_{rms}} = \sqrt {{{3RT} \over M}} $$
$${v_p} = \sqrt {{{2RT} \over M}} $$
$$ \Rightarrow {v_{rms}} = \sqrt {{3 \over 2}} {v_p}$$

Answer

$${v_{rms}} = \sqrt {{2 \over 3}} {v_p}$$

Answer

$${v_{rms}} = \sqrt {{3 \over 2}} {v_p}$$

Answer

$${v_{rms}} = {v_p}$$

Answer

$${v_{rms}} = \sqrt {{1 \over 3}} {v_p}$$

Thermodynamics & KTG

The relation between root mean square speed (v rms ) and most probable sped (v p ) for the molar mass M of oxygen gas molecule at the temperature of 300 K will be :

Choose the correct answer: