Question 62: Semiconductors and Logic Gates

Question

In an n-p-n common emitter (CE) transistor the collector current changes from 5 $\mathrm{mA}$ to $16 \mathrm{~mA}$ for the change in base current from $100~ \mu \mathrm{A}$ and $200 ~\mu \mathrm{A}$, respectively. The current gain of transistor is __________.

Accepted Answer

The current gain of a transistor in common emitter configuration is given by:
$\beta = \frac{I_C}{I_B}$
where $I_C$ is the collector current and $I_B$ is the base current.
In this case, the collector current changes from $5 \mathrm{~mA}$ to $16 \mathrm{~mA}$ for the change in base current from $100~ \mu \mathrm{A}$ to $200 ~\mu \mathrm{A}$. Therefore, we have:
$\Delta I_C = 16 \mathrm{~mA} - 5 \mathrm{~mA} = 11 \mathrm{~mA}$
$\Delta I_B = 200~ \mu \mathrm{A} - 100~ \mu \mathrm{A} = 100~ \mu \mathrm{A}$
Therefore, the current gain of the transistor is:
$\beta = \frac{\Delta I_C}{\Delta I_B} = \frac{11 \mathrm{~mA}}{100~ \mu \mathrm{A}} = 110$
Therefore, the current gain of the transistor is 110.

Answer

210

Answer

0.9

Answer

9

Answer

110

Semiconductors and Logic Gates

In an n-p-n common emitter (CE) transistor the collector current changes from 5 \mathrm{mA} to 16 \mathrm{~mA} for the change in base current from 100~ \mu \mathrm{A} and 200 ~\mu \mathrm{A}, respectively. The current gain of transistor is __________.

Choose the correct answer: