Question 64: Semiconductors and Logic Gates

Question

The logic performed by the circuit shown in figure is equivalent to :
![](https://app-content.cdn.examgoal.net/fly/@width/image/1lgveerhx/18c96f87-c326-4212-8faa-11dd08611cd3/ba879e50-e2ed-11ed-9a37-9d7cc94c05fd/file-1lgveerhy.png?format=png)

Accepted Answer

$
Y=\overline{\bar{a}+\overline{\mathrm{b}}}=a \cdot b
$
The truth table for the given circuit will be
$
\begin{array}{|c|c|c|}
\hline \mathrm{a} & \mathrm{b} & 	ext { output } \
\hline 0 & 0 & 0 \
\hline 0 & 1 & 0 \
\hline 1 & 0 & 0 \
\hline 1 & 1 & 1 \
\hline
\end{array}
$
Hence it will be equivalent to
AND
gate.
![](https://app-content.cdn.examgoal.net/fly/@width/image/1libatw7l/19597932-40fb-4f1c-b21e-d35139a53d2e/7c8f7c10-ff78-11ed-84fc-bb23324267e4/file-1libatw7m.png?format=png)

Answer

NAND

Answer

AND

Answer

OR

Answer

NOR

Semiconductors and Logic Gates

The logic performed by the circuit shown in figure is equivalent to :

Choose the correct answer: