Question 22: Semiconductors and Logic Gates

Question

In the following circuit, the reading of the ammeter will be
$($ Take Zener breakdown voltage $=4 \mathrm{~V})$

Accepted Answer

$$\mathrm{V}_1=\frac{400}{100+400} 	imes 12 \mathrm{~V}=\frac{4}{5} 	imes 12=\frac{48}{5} \mathrm{~V}$$
here, $\mathrm{V}_1>\mathrm{V}_{\mathrm{z}},\left(\mathrm{V}_{\mathrm{z}}=ight.$ Zener Voltage $)$
So, Zener breakdown will be take place So, voltage across $400 \Omega$ will be 4 V
$$\mathrm{I}=\frac{4}{400} \mathrm{~A}=\frac{1}{100 \mathrm{~A}}=10 \mathrm{~mA}$$

Answer

60 mA

Answer

80 mA

Answer

10 mA

Answer

24 mA

Semiconductors and Logic Gates

In the following circuit, the reading of the ammeter will be ( Take Zener breakdown voltage =4 \mathrm{~V})

Choose the correct answer: