Question 147: Ray Optics

Question

The aperture diameter of a telescope is 5m. The
separation between the moon and the earth is
4 × 10
5
km. With light of wavelength of
5500 $\mathop A\limits^o $, the minimum separation between
objects on the surface of moon, so that they are
just resolved, is close to :

Accepted Answer

$	heta $ = 1.22${\lambda  \over a}$
Distance O
1
O
2
= ($	heta $)d
= (1.22${\lambda  \over a}$)d
= ${{\left( {1.22} ight)\left( {5500 	imes {{10}^{ - 10}}} ight)\left( {4 	imes {{10}^5}} ight) 	imes {{10}^3}} \over 5}$
= 5368 ÃÂ 10
Ã¢ÂÂ2
m
= 53.68 m

Answer

20 m

Answer

200 m

Answer

600 m

Answer

60 m

Ray Optics

The aperture diameter of a telescope is 5m. The separation between the moon and the earth is 4 × 10 5 km. With light of wavelength of 5500 \mathop A\limits^o , the minimum separation between objects on the surface of moon, so that they are just resolved, is close to :

Choose the correct answer: