Question 103: Ray Optics

Question

Light enters from air into a given medium at an angle of $$45^{\circ}$$ with interface of the air-medium surface. After refraction, the light ray is deviated through an angle of 
$$15^{\circ}$$ from its original direction. The refractive index of the medium is:

Accepted Answer

Let, refractive index of medium = $$\mu$$
$$	herefore$$ $$r + 15^\circ  = 45^\circ $$
$$ \Rightarrow r = 30^\circ $$
Using Snell's law,
$$1\,.\,\sin 45^\circ  = \sin 30^\circ  	imes \mu $$
$$ \Rightarrow {1 \over {\sqrt 2 }} = {1 \over 2} 	imes \mu $$
$$ \Rightarrow \mu  = {2 \over {\sqrt 2 }} = \sqrt 2  = 1.414$$

Answer

1.732

Answer

1.333

Answer

1.414

Answer

2.732

Ray Optics

Light enters from air into a given medium at an angle of $45^{\circ} with interface of the air-medium surface. After refraction, the light ray is deviated through an angle of 15^{\circ}$ from its original direction. The refractive index of the medium is:

Choose the correct answer: