Question 116: Ray Optics

Question

Consider a light ray travelling in air is incident into a medium of refractive index $\sqrt{2n}$. The incident angle is twice that of refracting angle. Then, the angle of incidence will be :

Accepted Answer

According to the law,
$1 	imes \sin 	heta  = \sqrt {2n}  	imes \sin \left( {{	heta  \over 2}} ight)$
$ \Rightarrow \cos {	heta  \over 2} = \sqrt {{n \over 2}} $
$ \Rightarrow 	heta  = 2{\cos ^{ - 1}}\left( {\sqrt {{n \over 2}} } ight)$

Answer

${\sin ^{ - 1}}\left( {\sqrt n } \right)$

Answer

${\cos ^{ - 1}}\left( {\sqrt {{n \over 2}} } \right)$

Answer

${\sin ^{ - 1}}\left( {\sqrt {2n} } \right)$

Answer

$2{\cos ^{ - 1}}\left( {\sqrt {{n \over 2}} } \right)$

Ray Optics

Consider a light ray travelling in air is incident into a medium of refractive index \sqrt{2n}. The incident angle is twice that of refracting angle. Then, the angle of incidence will be :

Choose the correct answer: