Question 121: Ray Optics

Question

Two plane mirrors M
1
and M
2
are at right angle to each other shown. A point source 'P' is placed at 'a' and '2a' meter away from M
1
and M
2
respectively. The shortest distance between the images thus formed is : (Take $\sqrt 5 $ = 2.3)
![](https://imagex.cdn.examgoal.net/1ku4dcyq8/169c798b-3b90-4d95-9937-cf9a82dad824/b37f6d00-2083-11ec-b42c-25e6dbaf712c/file-1ku4dcyq9.jpg)

Accepted Answer

Shortest distance is 2a between I
1
& I
3
But answer given is for I
1
& I
2
= $\sqrt {{{(4a)}^2} + {{(2a)}^2}} $
= $a\sqrt {20} $
= 4.47 a
Option (b)
![](https://imagex.cdn.examgoal.net/1ku8ekblf/a81210e7-d4d3-45ab-b864-6fa315cf4fea/8bd3e030-22bb-11ec-92a0-35c33c2a328d/file-1ku8ekblg.png)

Answer

3a

Answer

4.6a

Answer

2.3a

Answer

2$\sqrt {10} $a

Ray Optics

Two plane mirrors M 1 and M 2 are at right angle to each other shown. A point source 'P' is placed at 'a' and '2a' meter away from M 1 and M 2 respectively. The shortest distance between the images thus formed is : (Take \sqrt 5 = 2.3)

Choose the correct answer: