Question 143: Properties of Matter

Question

The pressure acting on a submarine is 3 $$	imes$$ 10
5
Pa at a certain depth. If the depth is doubled, the percentage increase in the pressure acting on the submarine would be :
(Assume that atmospheric pressure is 1 $$	imes$$ 10
5
Pa density of water is 10
3
kg m
$$-$$3
, g = 10 ms
$$-$$2
)

Accepted Answer

P = P
0
+ h$$ho$$g = 3 $$	imes$$ 10
5
Pa
$$ \Rightarrow $$ h$$ho$$g = 3 $$	imes$$ 10
5
$$-$$ 1 $$	imes$$ 10
5
$$ \Rightarrow $$ h$$ho$$g = 2 $$	imes$$ 10
5
$$ 	herefore $$ 2h$$ho$$g = 4 $$	imes$$ 10
5
$$ 	herefore $$ P' = P
0
+ 4 $$	imes$$ 10
5
$$ 	herefore $$ P' = 5 $$	imes$$ 10
5
Pa
$$ 	herefore $$ % increase in pressure = $${{P' - P} \over P} 	imes 100$$
$$ = {{(5 - 3) 	imes {{10}^5}} \over {3 	imes {{10}^5}}} 	imes 100$$
$$ = {{200} \over 3}$$%

Answer

$${{200} \over 5}$$%

Answer

$${{200} \over 3}$$%

Answer

$${{3} \over 200}$$%

Answer

$${{5} \over 200}$$%

Properties of Matter

The pressure acting on a submarine is 3 $\times 10 5 Pa at a certain depth. If the depth is doubled, the percentage increase in the pressure acting on the submarine would be : (Assume that atmospheric pressure is 1 \times 10 5 Pa density of water is 10 3 kg m -3 , g = 10 ms -$2 )

Choose the correct answer: