Question 365: Properties of Matter

Question

The approximate depth of an ocean is 2700 m. The compressiblity of water is 45.4 $$ 	imes $$ 10
$$-$$11
Pa
$$-$$1
and density of water is 10
3
kg/m
3
. What fractional compression of water will be obtained at the bottom of the ocean?

Accepted Answer

Compressibility of water, K = 45.4 ÃÂ 10
Ã¢ÂÂ11
Pa
Ã¢ÂÂ1
density of water P = 10
3
kg/m
3
depth of ocean, h = 2700 m
We have to find $${{\Delta V} \over V} = ?$$
As we know, compressibility,
$$K = {1 \over B} = {{\left( {\Delta V/V} \right)} \over P}\left( {P = \rho gh} \right)$$
So, $$\left( {{{\Delta V} \over V}} \right) = K\rho gh$$
= 45.4 ÃÂ 10
Ã¢ÂÂ11
ÃÂ 10
3
ÃÂ 10 ÃÂ 2700  = 1.2258 ÃÂ 10
Ã¢ÂÂ2

Answer

1.2 $$ 	imes $$ 10
$$-$$2

Answer

1.4 $$ 	imes $$ 10
$$-$$2

Answer

0.8 $$ 	imes $$ 10
$$-$$2

Answer

1.0 $$ 	imes $$ 10
$$-$$2

Properties of Matter

The approximate depth of an ocean is 2700 m. The compressiblity of water is 45.4 $ \times 10 -11 Pa -$1 and density of water is 10 3 kg/m 3 . What fractional compression of water will be obtained at the bottom of the ocean?

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