Question 249: Oscillations

Question

A simple pendulum of length ' $L$ ' has mass ' $M$ ' and it oscillates freely with amplitude ' $A$ '. At extreme position, its potential energy is

Accepted Answer

$$\begin{aligned}
&	ext { Potential energy of particle at extreme position is}\
&\begin{aligned}
& \mathrm{P.E.}=\frac{1}{2} M \omega^2 A^2 \
& =\frac{1}{2} M 	imes \frac{g}{L} 	imes A^2 \quad \ldots . .\left(\because \omega=\sqrt{\frac{g}{l}}ight)
\end{aligned}
\end{aligned}
$$

Answer

$\frac{\mathrm{MgA}^2}{\mathrm{~L}}$

Answer

$\frac{2 \mathrm{MgA}^2}{\mathrm{~L}}$

Answer

$\frac{\mathrm{MgA}}{2 \mathrm{~L}}$

Answer

$\frac{\mathrm{MgA}^2}{2 \mathrm{~L}}$

Oscillations

A simple pendulum of length ' L ' has mass ' M ' and it oscillates freely with amplitude ' A '. At extreme position, its potential energy is

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