Question 268: Oscillations

Question

A small sphere oscillates simple harmonically in a watch glass whose radius of curvature is 1.6 m . The period of oscillation of the sphere in second is (acceleration due to gravity, $\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2$ )

Accepted Answer

$$\begin{aligned}
\mathrm{T} & =2 \pi \sqrt{\frac{l}{\mathrm{~g}}} \
& =2 \pi \sqrt{\frac{1.6}{10}} \quad \ldots(\because \mathrm{R}=l) \
& =0.8 \pi
\end{aligned}$$

Answer

$0.8 \pi$

Answer

$0.6 \pi$

Answer

$0.4 \pi$

Answer

$0 \cdot 2 \pi$

Oscillations

A small sphere oscillates simple harmonically in a watch glass whose radius of curvature is 1.6 m . The period of oscillation of the sphere in second is (acceleration due to gravity, \mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2 )

Choose the correct answer: