Question 52: Oscillations

Question

The maximum potential energy of a block executing simple harmonic motion is $25 \mathrm{~J}$. A is amplitude of oscillation. At $\mathrm{A / 2}$, the kinetic energy of the block is

Accepted Answer

$\mathrm{U}_{\max }=\frac{1}{2} \mathrm{~m} \omega^{2} \mathrm{~A}^{2}=25 \mathrm{~J}$
$\mathrm{KE}$ at $\frac{\mathrm{A}}{2}=\frac{1}{2} m v_{1}^{2}=\frac{1}{2} m \omega^{2}\left(A^{2}-\frac{A^{2}}{4}ight)$
$=\frac{1}{2} \mathrm{~m} \omega^{2} \frac{3 \mathrm{~A}^{2}}{4}=\frac{3}{4}\left(\frac{1}{2} \mathrm{~m} \omega^{2} \mathrm{~A}^{2}ight)$
$\mathrm{KE}=\frac{3}{4} 	imes 25=18.75 \mathrm{~J}$

Answer

9.75 J

Answer

37.5 J

Answer

18.75 J

Answer

12.5 J

Oscillations

The maximum potential energy of a block executing simple harmonic motion is 25 \mathrm{~J}. A is amplitude of oscillation. At \mathrm{A / 2}, the kinetic energy of the block is

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