Question 200: Magnetism and Matter

Question

Find the magnetic field at point P due to a straight line segment AB of length 6 cm carrying a current of 5A.
(See figure) ($\mu $
0
= 4$\pi $ × 10
–7
N-A
–2
)
![](https://imagex.cdn.examgoal.net/jf762wkjxtr8qzh/bb1ea901-970b-4b9f-bcc8-971e842c7ebc/72d1c4d0-a126-11e9-902e-23ffedc9804e/file-jf762wkjxtr8qzi.png)

Accepted Answer

B = ${{{\mu _0}I} \over {4\pi r}}\left( {\sin {	heta _1} + \sin {	heta _2}} ight)$
As $	heta $
1
= $	heta $
2
= $	heta $
B = ${{{\mu _0}I} \over {4\pi r}}\left( {2\sin 	heta } ight)$
= ${{{{10}^{ - 7}} 	imes 5} \over {4 	imes {{10}^{ - 2}}}} 	imes 2 	imes {3 \over 5}$
= 1.5 $ 	imes $ 10
-5
T
![](https://imagex.cdn.examgoal.net/jf762wkjxtrf7s6/30a70a4e-1e31-4708-a6ff-e087b5fdfa96/26a64c60-a127-11e9-902e-23ffedc9804e/file-jf762wkjxtrf7s7.png)

Answer

1.5 × 10
–5
T

Answer

3.0 × 10
–5
T

Answer

2.0 × 10
–5
T

Answer

2.5 × 10
–5
T

Magnetism and Matter

Find the magnetic field at point P due to a straight line segment AB of length 6 cm carrying a current of 5A. (See figure) (\mu 0 = 4\pi × 10 –7 N-A –2 )

Choose the correct answer: