Question 66: Magnetism and Matter

Question

At an angle of 30$$^\circ$$ to the magnetic meridian, the apparent dip is 45$$^\circ$$. Find the true dip :

Accepted Answer

$$A	an \delta  = 	an \delta '\cos 	heta $$
$$ = 	an 45^\circ \cos 30^\circ $$
$$	an \delta  = 1 	imes {{\sqrt 3 } \over 2}$$
$$\delta  = {	an ^{ - 1}}\left( {{{\sqrt 3 } \over 2}} ight)$$

Answer

$${	an ^{ - 1}}\sqrt 3 $$

Answer

$${	an ^{ - 1}}{1 \over {\sqrt 3 }}$$

Answer

$${	an ^{ - 1}}{2 \over {\sqrt 3 }}$$

Answer

$${	an ^{ - 1}}{{\sqrt 3 } \over 2}$$

Magnetism and Matter

At an angle of 30$^\circ to the magnetic meridian, the apparent dip is 45^\circ$. Find the true dip :

Choose the correct answer: