Question 183: Magnetism and Matter

Question

An iron rod of volume 10
–3
m
3
and relative
permeability 1000 is placed as core in a
solenoid with 10 turns/cm. If a current of 0.5 A
is passed through the solenoid, then the
magnetic moment of the rod will be :

Accepted Answer

Given, V = 10
Ã¢ÂÂ3
m
3
= Al
I = 0.5A
$$\mu $$
r
= 1000
n = 10 turns/cm = $${{10} \over {{{10}^{ - 2}}}}$$ turn/m = 1000 turn/m
Magnetic moment, M = NIA($$\mu $$
r
- 1)
= (nl)IA($$\mu $$
r
- 1)
= nI(Al)($$\mu $$
r
- 1)
= 1000 ÃÂ 0.5 ÃÂ 10
Ã¢ÂÂ3
(1000 Ã¢ÂÂ 1)
= 0.5 ÃÂ (999) = 499.5
$$ \simeq $$ 500 = 5 $$ 	imes $$ 10
2
Am
2

Answer

5 $$ 	imes $$ 10
2
Am
2

Answer

0.5 $$ 	imes $$ 10
2
Am
2

Answer

500 $$ 	imes $$ 10
2
Am
2

Answer

50 $$ 	imes $$ 10
2
Am
2

Magnetism and Matter

An iron rod of volume 10 –3 m 3 and relative permeability 1000 is placed as core in a solenoid with 10 turns/cm. If a current of 0.5 A is passed through the solenoid, then the magnetic moment of the rod will be :

Choose the correct answer: