Question 217: Laws of Motion

Question

In the diagram shown, the normal reaction force between 2 kg and 1 kg is (Consider the surface, to be smooth) :
(Given g  = 10 ms
$-$2
)
![](https://app-content.cdn.examgoal.net/fly/@width/image/1lab1c9mu/11d39aa6-aeae-442c-a76b-d13c09390cb5/a52bf660-60f1-11ed-b81b-f1e44e9e12b2/file-1lab1c9mv.png?format=png)

Accepted Answer

Assuming all three blocks as system
Hence, acceleration of system
$a = {{60 - 30 - 18} \over 6} = {{12} \over 6} = 2$ m/s
2
$a = 2$ m/s
2
, upward along the incline.
Now, for 1 kg block
$ \Rightarrow {N_{12}} - 18 - 5 = 1 	imes 2$
$ \Rightarrow {N_{12}} - 23 = 2$
$ \Rightarrow {N_{12}} = 25$ N
![](['https://app-content.cdn.examgoal.net/fly/@width/image/1lab1db1o/65952dd3-698a-4e02-b60d-2785d1561694/c21256c0-60f1-11ed-b81b-f1e44e9e12b2/file-1lab1db1p.png?format=png', 'https://app-content.cdn.examgoal.net/fly/@width/image/1lab1dzuf/fda06e2d-0509-4935-b56b-e9b8546f5e65/d53a5c70-60f1-11ed-b81b-f1e44e9e12b2/file-1lab1dzug.png?format=png'])

Answer

10 N

Answer

25 N

Answer

39 N

Answer

6 N

Laws of Motion

In the diagram shown, the normal reaction force between 2 kg and 1 kg is (Consider the surface, to be smooth) : (Given g = 10 ms -2 )

Choose the correct answer: