Question 575: Electrostatics & Capacitance

Question

In the given figure potential at point 'A' is 900 volt and point 'B' is earthed. What will be the potential at point 'P' ?
![](https://app-content.cdn.examgoal.net/fly/@width/image/jaoe38c1lxvdpo4x/c97cfc92-51f1-4df1-b6c1-aa149c2e1efe/ae256e10-337a-11ef-982a-730d6739f3ba/file-jaoe38c1lxvdpo4y.png?format=png)

Accepted Answer

Capacitors $\mathrm{C}_2$ and $\mathrm{C}_3$ are in parallel. Hence their equivalent capacitance
$\mathrm{C}_4=\mathrm{C}_2+\mathrm{C}_3=8+4=12 \mu \mathrm{F}$
$\mathrm{C}_4$ and $\mathrm{C}_1$ are in series.
Their equivalent capacitance $\mathrm{C}=\frac{12 	imes 6}{12+6}=\frac{72}{18}=4 \mu \mathrm{F}$
Charge stored by the combination
$\mathrm{q}=\mathrm{CV}=4 	imes 900$
$=3600 \mu \mathrm{C}$
In the series combination, change in same on each capacitor.
$	herefore$ Charge on $\mathrm{C}_1=3600 \mu \mathrm{C}$
$P, D$, across $C_1$ is $V_1=\frac{q}{C_1}=\frac{3600}{6}=600 \mathrm{~V}$
$\begin{aligned}
& 	herefore V_A-V_P=600 \quad 	herefore 900-V_P=600 \\
& 	herefore V_P=300 V
\end{aligned}$

Answer

900 V

Answer

100 V

Answer

300 V

Answer

600 V

Electrostatics & Capacitance

In the given figure potential at point 'A' is 900 volt and point 'B' is earthed. What will be the potential at point 'P' ?

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