Question 758: Electrostatics & Capacitance

Question

A charge Q is enclosed  by a Gaussian spherical surface of radius R. If the radius is doubled, then the outward electric flux will

Accepted Answer

According to GaussÃ¢ÂÂs law
$${\phi _E} = {{{Q_{enclosed}}} \over {{\varepsilon _0}}}$$
If the radius of the Gaussian surface is doubled, the outward electric flux will remain the same. This is because electric flux depends only on the charge enclosed by the surface.

Answer

increase four times

Answer

be reduced to half

Answer

remain the same

Answer

be doubled

Electrostatics & Capacitance

A charge Q is enclosed by a Gaussian spherical surface of radius R. If the radius is doubled, then the outward electric flux will

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