Question 260: Electrostatics & Capacitance

Question

Two capacitors having capacitance C
1
and C
2
respectively are connected as shown in figure. Initially, capacitor C
1
is charged to a potential difference V volt by a battery. The battery is then removed and the charged capacitor C
1
is now connected to uncharged capacitor C
2
by closing the switch S. The amount of charge on the capacitor C
2
, after equilibrium, is :
![](https://app-content.cdn.examgoal.net/fly/@width/image/1l5bpfbsc/582c329c-0436-45b7-a96d-f41af4a9ecf3/c0779ac0-fe52-11ec-b169-b5046c590266/file-1l5bpfbsd.png?format=png)

Accepted Answer

$
V_{	ext {common }}=\frac{C_1 V}{C_1+C_2}
$
$\Rightarrow$ Charge on capacitor $C_2$

Answer

${{{C_1}{C_2}} \over {({C_1} + {C_2})}}V$

Answer

${{({C_1} + {C_2})} \over {{C_1}{C_2}}}V$

Answer

$({C_1} + {C_2})V$

Answer

$({C_1} - {C_2})V$

Electrostatics & Capacitance

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