Question 260: Electrostatics & Capacitance

Question

Two capacitors having capacitance C
1
and C
2
respectively are connected as shown in figure. Initially, capacitor C
1
is charged to a potential difference V volt by a battery. The battery is then removed and the charged capacitor C
1
is now connected to uncharged capacitor C
2
by closing the switch S. The amount of charge on the capacitor C
2
, after equilibrium, is :

Accepted Answer

$$
V_{	ext {common }}=\frac{C_1 V}{C_1+C_2}
$$
$\Rightarrow$ Charge on capacitor $C_2$

Answer

$${{{C_1}{C_2}} \over {({C_1} + {C_2})}}V$$

Answer

$${{({C_1} + {C_2})} \over {{C_1}{C_2}}}V$$

Answer

$$({C_1} + {C_2})V$$

Answer

$$({C_1} - {C_2})V$$

Electrostatics & Capacitance

Choose the correct answer: