Question 388: Electrostatics & Capacitance

Question

The figure shows an experimental plot for discharging of a capacitor in an R-C circuit. The time constant $	au $ of this circuit lies between
![](https://imagex.cdn.examgoal.net/1qpqahkk8fhfebj/297ff631-178c-4b79-bfa7-9a6a829671e0/787c0cf0-7313-11ea-aedc-f1c8d8e0194b/file-1qpqahkk8fhfebk-320w.png)

Accepted Answer

During discharging of a capacitor, V = V
0
${e^{ - {t \over 	au }}}$
At t = $	au $,
V = ${{{V_0}} \over e}$ = 0.37V
0
From the graph, t = 0, V
0
= 25 V
$ 	herefore $ V = 0.37 $ 	imes $ 25 = 9.25 V
This voltage will occur at time between 100 sec and 150 sec. Hence, time constant $	au $ of this circuit lies between 100 sec and 150 sec.

Answer

100 sec and 150 sec

Answer

0 and 50 sec

Answer

50 sec and 100 sec

Answer

150 sec and 200 sec

Electrostatics & Capacitance

The figure shows an experimental plot for discharging of a capacitor in an R-C circuit. The time constant \tau of this circuit lies between

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