Question 388: Electrostatics & Capacitance

Question

The figure shows an experimental plot for discharging of a capacitor in an R-C circuit. The time constant $$	au $$ of this circuit lies between

Accepted Answer

During discharging of a capacitor, V = V
0
$${e^{ - {t \over 	au }}}$$
At t = $$	au $$,
V = $${{{V_0}} \over e}$$ = 0.37V
0
From the graph, t = 0, V
0
= 25 V
$$ 	herefore $$ V = 0.37 $$ 	imes $$ 25 = 9.25 V
This voltage will occur at time between 100 sec and 150 sec. Hence, time constant $$	au $$ of this circuit lies between 100 sec and 150 sec.

Answer

100 sec and 150 sec

Answer

0 and 50 sec

Answer

50 sec and 100 sec

Answer

150 sec and 200 sec

Electrostatics & Capacitance

The figure shows an experimental plot for discharging of a capacitor in an R-C circuit. The time constant $\tau $ of this circuit lies between

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