Question 321: Electrostatics & Capacitance

Question

In the given circuit, the charge on 4 $\mu $F capacitor will be :

Accepted Answer

As V = ${q \over C}$
$ 	herefore $ V $ \propto $ ${1 \over C}$
So ${{{V_1}} \over {{V_2}}} = {{{C_2}} \over {{C_1}}}$
$ \Rightarrow $ ${{{V_1}} \over {{V_2}}} = {6 \over 4} = {3 \over 2}$
Also V
1
+ V
2
= 10
$ 	herefore $ V
1
+ ${2 \over 3}$V
1
= 10
$ \Rightarrow $ ${{5{V_1}} \over 3}$ = 10
$ \Rightarrow $ V
1
= 6 V
The charge on 4 $\mu $F capacitor is = C
1
V
1
= 4 $ 	imes $ 6 = 24 $\mu $C

Answer

5.4 $\mu $C

Answer

9.6 $\mu $C

Answer

13.4 $\mu $C

Answer

24 $\mu $C

Electrostatics & Capacitance

In the given circuit, the charge on 4 \mu F capacitor will be :

Choose the correct answer: