Question 215: Electrostatics & Capacitance

Question

A point charge $+q$ is placed at the origin. A second point charge $+9 q$ is placed at ($\mathrm{d}, 0,0$) in Cartesian coordinate system. The point in between them where the electric field vanishes is:

Accepted Answer

Let $E_p=0$
$$\begin{aligned}
& 	herefore \frac{k q}{x^2}=\frac{k 9 q}{(d-x)^2} \
& \Rightarrow \frac{d-x}{x}=3 \Rightarrow x=\frac{d}{4}
\end{aligned}$$
$	herefore$ co-ordinate of P is $\left(\frac{\mathrm{d}}{4}, 0,0ight)$

Answer

$(3 \mathrm{d} / 4,0,0)$

Answer

$(\mathrm{d} / 4,0,0)$

Answer

$(4 \mathrm{d} / 3,0,0)$

Answer

$(\mathrm{d} / 3,0,0)$

Electrostatics & Capacitance

A point charge +q is placed at the origin. A second point charge +9 q is placed at (\mathrm{d}, 0,0) in Cartesian coordinate system. The point in between them where the electric field vanishes is:

Choose the correct answer: