Question 766: Electrostatics & Capacitance

Question

The electric potential at a point in free space due to charge Q coulomb is Q $$ 	imes $$ 10
11
volts. The electric field at that point is

Accepted Answer

$$V = {1 \over {4\pi {\varepsilon _0}}} 	imes {Q \over R}$$
= Q ÃÂ 10
11
volt      Ã¢ÂÂ¦(i)
$$E = {1 \over {4\pi {\varepsilon _0}}} 	imes {Q \over {{R^2}}}$$
= V/R = Q ÃÂ 10
11
ÃÂ $${4\pi {\varepsilon _0}}$$ ÃÂ 10
11
from ...(i)
= $${4\pi {\varepsilon _0}}$$  ÃÂ Q ÃÂ 10
22
volt/m

Answer

$$4\pi {\varepsilon _0}Q 	imes {10^{20}}$$ volt/m

Answer

12$$\pi $$
0
Q $$ 	imes $$ 10
22
volt/m

Answer

$$4\pi {\varepsilon _0}Q 	imes {10^{22}}$$ volt/m

Answer

$$12\pi {\varepsilon _0}Q 	imes {10^{20}}$$ volt/m

Electrostatics & Capacitance

The electric potential at a point in free space due to charge Q coulomb is Q $ \times $ 10 11 volts. The electric field at that point is

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