Question 631: Electrostatics & Capacitance

Question

A parallel plate capacitor  of capacitance 20 $$\mu $$F is being charged by a voltage source whose potential is changing at the rate of 3V/s. The conduction current through the connecting wires, and the displacement current through the plates of the capacitor, would be, respectively :

Accepted Answer

As, q = CV
Differentiating above equation w.r.t. t, we get
$${{dq} \over {dt}} = C{{dV} \over {dt}}$$
$$ \Rightarrow $$ i
c
= $$C{{dV} \over {dt}}$$ [As i = $${{dq} \over {dt}}$$]
= 20 $$ 	imes $$ 10
-6
$$ 	imes $$ 3
= 60 $$ 	imes $$ 10
-6
A = 60$$\mu $$A
Also, conduction current in wires is equal to displacement current between the plates of capacitor.
$$ 	herefore $$  i
d
= i
c
= 60 $$\mu $$A

Answer

zero, zero

Answer

zero, 60 $$\mu $$A

Answer

60 $$\mu $$A, 60 $$\mu $$A

Answer

60 $$\mu $$A, zero

Electrostatics & Capacitance

A parallel plate capacitor of capacitance 20 $\mu $F is being charged by a voltage source whose potential is changing at the rate of 3V/s. The conduction current through the connecting wires, and the displacement current through the plates of the capacitor, would be, respectively :

Choose the correct answer: