Question 18: Electrostatics & Capacitance

Question

A parallel plate capacitor has an electric field of $10^5 \mathrm{~Vm}^{-1}$ between the plates. If the charge on the capacitor plates is $1 \mu \mathrm{C}$, the force on each capacitor plate is

Accepted Answer

Net charge on the parallel plate capacitor is $1 \mu \mathrm{C}$
Electric field near one of the Plates due to the other plate is $E=\frac{10^5}{2} \mathrm{~Vm}^{-1}$
Now, force is given by
$\begin{aligned}
\qquad F & =q E \
	ext { Substituting } q & =1 \mu \mathrm{C}=1 	imes 10^{-6} \mathrm{C} \
	ext { We get } \quad F & =0 \cdot 05 \mathrm{~N}
\end{aligned}$

Answer

0.5 N

Answer

0.05 N

Answer

0.005 N

Answer

None of these

Electrostatics & Capacitance

A parallel plate capacitor has an electric field of 10^5 \mathrm{~Vm}^{-1} between the plates. If the charge on the capacitor plates is 1 \mu \mathrm{C}, the force on each capacitor plate is

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