Question 342: Electromagnetic Induction

Question

A long solenoid has 500 turns. When a current of 2 ampere is passed through it, the resulting magnetic flux linked with each turn of the solenoid is 4 $$ 	imes $$ 10
$$-$$3
Wb. The self-inductance of the solenoid is

Accepted Answer

Total number of turns in the solenoid,
N = 500 Current, I = 2A.
Magnetic flux linked with each turn = 4 ÃÂ 10
Ã¢ÂÂ3
Wb
Self inductance of coil :
L = $${{N\phi } \over I} = {{500 	imes 4 	imes {{10}^3}} \over 2}$$ = 1 H

Answer

1.0 henry

Answer

4.0 henry

Answer

2.5 henry

Answer

2.0 henry

Electromagnetic Induction

A long solenoid has 500 turns. When a current of 2 ampere is passed through it, the resulting magnetic flux linked with each turn of the solenoid is 4 $ \times 10 -$3 Wb. The self-inductance of the solenoid is

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