Question 132: Dual Nature of Matter and Radiation

Question

A moving proton and electron have the same de-Broglie wavelength. If K and P denote the K.E. and momentum respectively. Then choose the correct option :

Accepted Answer

$${\lambda _p} = {h \over {{P_p}}}$$
$${\lambda _e} = {h \over {{P_e}}}$$
$$\because$$ $${\lambda _p} = {\lambda _e}$$
$$ \Rightarrow {P_p} = {P_e}$$
$${(K)_p} = {{P_p^2} \over {2{m_p}}}$$
$${(K)_e} = {{P_e^2} \over {2{m_e}}}$$
K
p
 m
e
Option (a)

Answer

K
p
< K
e
and P
p
= P
e

Answer

K
p
= K
e
and P
p
= P
e

Answer

K
p
< K
e
an P
p
< P
e

Answer

K
p
> K
e
and P
p
= P
e

Dual Nature of Matter and Radiation

A moving proton and electron have the same de-Broglie wavelength. If K and P denote the K.E. and momentum respectively. Then choose the correct option :

Choose the correct answer: