Question 153: Dual Nature of Matter and Radiation

Question

An electron of mass m
e
and a proton of mass m
p
= 1836 m
e
are moving with the same speed. The ratio of their de Broglie wavelength $${{{}^\lambda electron} \over {{}^\lambda proton}}$$ will be :

Accepted Answer

Given mass of electron = m
e
Mass of proton = m
p
$$ 	herefore $$ given m
p
= 1836 m
e
From de-Broglie wavelength
$$\lambda  = {h \over p} = {h \over {mv}}$$
$${{{\lambda _e}} \over {{\lambda _p}}} = {{{m_p}} \over {{m_e}}}$$
$$ = {{1836{m_e}} \over {{m_e}}}$$
$${{{\lambda _e}} \over {{\lambda _p}}} = 1836$$

Answer

1

Answer

1836

Answer

$${1 \over {1836}}$$

Answer

918

Dual Nature of Matter and Radiation

An electron of mass m e and a proton of mass m p = 1836 m e are moving with the same speed. The ratio of their de Broglie wavelength ${{{}^\lambda electron} \over {{}^\lambda proton}}$ will be :

Choose the correct answer: