Question 4: Dual Nature of Matter and Radiation

Question

The stopping potential (V
0
) versus frequency $
u $ of a graph for photoelectric effect in a metal. From the graph, the Plank's constant (h) is
![](https://app-content.cdn.examgoal.net/fly/@width/image/1lhvj9dhn/d7049738-c335-425e-aff6-2ae9ddc09ef0/e9b025b0-f6cc-11ed-8ced-6f6ce6f31022/file-1lhvj9dho.png?format=png)

Accepted Answer

$e{V_0} = h(
u  - {
u _0}) = h
u  - h{
u _0}$
${V_0} = \left( {{h \over e}} ight)
u  - \left( {{h \over e}} ight){
u _0}$ ..... (i)
From Eq. (i), it follows that the slope of the graph is ${h \over e}$.
Therefore,
h = e $	imes$ slope = 1.6 $	imes$ 10
$-$19
$	imes$ ${{16.5 - 0} \over {(8 - 4) 	imes {{10}^{15}}}}$
$ = {{1.6 	imes {{10}^{ - 19}} 	imes 16.5} \over {4 	imes {{10}^{ - 5}}}} = 6.6 	imes {10^{ - 34}}$ J-s.

Answer

6.60 $	imes$ 10
$-$34
J-s

Answer

6.69 $	imes$ 10
$-$34
J-s

Answer

6.62 $	imes$ 10
$-$34
J-s

Answer

6.63 $	imes$ 10
$-$34
J-s

Dual Nature of Matter and Radiation

The stopping potential (V 0 ) versus frequency \nu of a graph for photoelectric effect in a metal. From the graph, the Plank's constant (h) is

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