Question 669: Current Electricity

Question

Power dissipated across the 8 $\Omega $ resistor in the circuit shown here is 2 watt. The power dissipated in watt units across the 3 $\Omega $ resistor is

Accepted Answer

Power = V . I = I
2
R
${i_2} = \sqrt {{{Power} \over R}}  = \sqrt {{2 \over 8}} $
= $\sqrt {{1 \over 4}}  = {1 \over 2}A$
Potential over $8\Omega  = R{i_2} = 8 	imes {1 \over 2} = 4V$
This is the potential over parallel branch. So,
${i_1} = {4 \over 4} = 1A$
Power of $3\Omega  = {i_1}^2R = 1 	imes 1 	imes 3 = 3W$

Answer

3.0

Answer

2.0

Answer

1.0

Answer

0.5

Current Electricity

Power dissipated across the 8 \Omega resistor in the circuit shown here is 2 watt. The power dissipated in watt units across the 3 \Omega resistor is

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