Question 341: Current Electricity

Question

The resistive network shown below is connected to a D.C. source of 16 V. The power consumed by the
network is 4 Watt. The value of R is:
![](https://imagex.cdn.examgoal.net/7kejek1bnozla/4dadef7f-2847-4f21-a9e5-db2f664209a7/53b914e0-e663-11e9-a7bc-b7b08ce8d541/file-7kejek1bnozlb-310w.jpg)

Accepted Answer

R
eq
= 2R + R + 4R + R = 8R
$P = {{{v^2}} \over {{R_{eq}}}} \Rightarrow {{16 	imes 16} \over {8R}} = 4\,watt$
${{16 	imes 16} \over {4 	imes 8}} = R \Rightarrow R = 8\Omega $

Answer

16 $\Omega $

Answer

1 $\Omega $

Answer

8 $\Omega $

Answer

6 $\Omega $

Current Electricity

The resistive network shown below is connected to a D.C. source of 16 V. The power consumed by the network is 4 Watt. The value of R is:

Choose the correct answer: