Question 302: Current Electricity

Question

In the given figure, the emf of the cell is 2.2 V and if internal resistance is 0.6$$\Omega$$. Calculate the power dissipated in the whole circuit :

Accepted Answer

$${1 \over {{R_{eq}}}} = {1 \over 4} + {1 \over 8} + {1 \over {12}} + {1 \over 6} = {{6 + 3 + 2 + 4} \over {24}} = {{15} \over {24}}$$
$${R_{eq}} = {{24} \over {15}} = 1.6 \Rightarrow {R_T} = 1.6 + 0.6 = 2.2\,\Omega $$
$$P = {{{V^2}} \over {{R_T}}} = {{{{(2.2)}^2}} \over {2.2}} = 2.2W$$
Option (c)

Answer

1.32 W

Answer

0.65 W

Answer

2.2 W

Answer

4.4 W

Current Electricity

In the given figure, the emf of the cell is 2.2 V and if internal resistance is 0.6$\Omega$. Calculate the power dissipated in the whole circuit :

Choose the correct answer: