Question 524: Current Electricity

Question

Only $4 \%$ of the total current in the circuit passes through a galvanometer. If the resistance of the galvanometer is $G$, then the shunt resistance connected to the galvanometer is

Accepted Answer

From the given figure, we have $\left(I-I_Gight) S=I_G G$
Image
$\Rightarrow \quad S=\frac{I_G G}{\left(I-I_Gight)}$
$	ext { Here, } I_G=\frac{4 I}{100}=\frac{I}{25}$
$\begin{aligned}
	herefore \quad S & =\frac{\frac{1}{25} 	imes G}{I-\frac{1}{25}} \
& =\frac{\frac{G}{25}}{\frac{24}{25}}=\frac{1}{24} 	imes G \
& =\frac{G}{24}
\end{aligned}$

Answer

$\frac{G}{25}$

Answer

$\frac{G}{24}$

Answer

24G

Answer

25G

Current Electricity

Only 4 \% of the total current in the circuit passes through a galvanometer. If the resistance of the galvanometer is G, then the shunt resistance connected to the galvanometer is

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