Question 656: Current Electricity

Question

The mean free path of electrons in a metal is 4 $ 	imes $ 10
$-$8
m. The electric field which can give on an average 2 eV energy to an electron in the metal will be in units V/m

Accepted Answer

Given, Energy = 2 eV = eE$\lambda $
$ 	herefore $ E = ${{2eV} \over {e\lambda }} = {2 \over {4 	imes {{10}^{ - 8}}}} = 5 	imes {10^7}$ V/m

Answer

$5 	imes {10^{ - 11}}$

Answer

8 $ 	imes $  10
$-$11

Answer

5 $ 	imes $ 10
7

Answer

8 $ 	imes $ 10
7

Current Electricity

The mean free path of electrons in a metal is 4 \times 10 -8 m. The electric field which can give on an average 2 eV energy to an electron in the metal will be in units V/m

Choose the correct answer: