Question 496: Current Electricity

Question

The potential difference $\left(V_A-V_B\right)$ between the points ' $A$ ' and ' $B$ ' in the given part of the circuit is

Accepted Answer

Given circuit can also be drawn as,
By Kirchhoff's voltage law,
$$V_A-(2 	imes 2)-(3)-(2 	imes 1)-V_B=0$$
$$\begin{array}{ll}
	herefore & \mathrm{V}_{\mathrm{A}}-4-3-2-\mathrm{V}_{\mathrm{B}}=0 \
	herefore & \mathrm{~V}_{\mathrm{A}}-\mathrm{V}_{\mathrm{B}}=+9 \mathrm{~V}
\end{array}$$

Answer

$-$3 V

Answer

3 V

Answer

6 V

Answer

9 V

Current Electricity

The potential difference \left(V_A-V_B\right) between the points ' A ' and ' B ' in the given part of the circuit is

Choose the correct answer: