Question 496: Current Electricity

Question

The potential difference $\left(V_A-V_B\right)$ between the points ' $A$ ' and ' $B$ ' in the given part of the circuit is
![](https://app-content.cdn.examgoal.net/fly/@width/image/jaoe38c1m4mysxow/cc8b6102-d555-43a8-a24e-be12059e53cd/9e796900-b96f-11ef-b9ca-c562d6f2f778/file-jaoe38c1m4mysxox.png?format=png)

Accepted Answer

Given circuit can also be drawn as,
By Kirchhoff's voltage law,
$V_A-(2 	imes 2)-(3)-(2 	imes 1)-V_B=0$
$\begin{array}{ll}
	herefore & \mathrm{V}_{\mathrm{A}}-4-3-2-\mathrm{V}_{\mathrm{B}}=0 \
	herefore & \mathrm{~V}_{\mathrm{A}}-\mathrm{V}_{\mathrm{B}}=+9 \mathrm{~V}
\end{array}$
![](https://app-content.cdn.examgoal.net/fly/@width/image/jaoe38c1m4myu4q0/f664e9bd-e2da-44c8-89a3-412e7734df32/bfb6ee80-b96f-11ef-b9ca-c562d6f2f778/file-jaoe38c1m4myu4q1.png?format=png)

Answer

$-$3 V

Answer

3 V

Answer

6 V

Answer

9 V

Current Electricity

The potential difference \left(V_A-V_B\right) between the points ' A ' and ' B ' in the given part of the circuit is

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