Question 106: Current Electricity

Question

In the circuit diagram shown in figure given below, the current flowing through resistance $$3 ~\Omega$$ is $$\frac{x}{3} A$$.
The value of $$x$$ is ___________

Accepted Answer

$$
\mathrm{E}_2-\mathrm{E}_1=8-4=4 \mathrm{~V}
$$
$$
\begin{aligned}
& \frac{1}{3}+\frac{1}{6}=\frac{1}{2}=\frac{1}{R} \\
& R=2 \Omega
\end{aligned}
$$
$$
I=\frac{4}{8}=0.5 \mathrm{~A}
$$
$$
\begin{aligned}
& \mathrm{I}_1=\left(\frac{6}{3+6}ight) 	imes 0.5 \\
& \mathrm{I}_1=\frac{2}{3} 	imes 0.5=\frac{1}{3} \mathrm{~A}
\end{aligned}
$$
$$
I_1=\frac{x}{3}=\frac{1}{3} 	herefore x=1
$$

Current Electricity

In the circuit diagram shown in figure given below, the current flowing through resistance $3 ~\Omega is \frac{x}{3} A. The value of x$ is ___________

Integer / Numeric Answer Type