Question 307: Current Electricity

Question

The given potentiometer has its wire of resistance 10$$\Omega$$. When the sliding contact is in the middle of the potentiometer wire, the potential drop across 2$$\Omega$$ resistor is :

Accepted Answer

$${{20 - {V_0}} \over 5} + {{0 - {V_0}} \over 5} + {{20 - {V_0}} \over 2} = 0$$
$$4 + 10 = {{2{V_0}} \over 5} + {{{V_0}} \over 2}$$
$$14 = {{4{V_0} + 5{V_0}} \over {10}}$$
$${V_0} = {{140} \over 9}$$ Volt
Potential difference across 2$$\Omega$$ resistor is 20 $$-$$ V
0
That is $$\left( {20 - {{140} \over 9}} \right)$$ Volt
Hence answer is $$\left( {{{40} \over 9}} \right)$$ Volt

Answer

10 V

Answer

5 V

Answer

$${{40} \over 9}$$ V

Answer

$${{40} \over 11}$$ V

Current Electricity

The given potentiometer has its wire of resistance 10$\Omega. When the sliding contact is in the middle of the potentiometer wire, the potential drop across 2\Omega$ resistor is :

Choose the correct answer: