Question 392: Current Electricity

Question

In a meter bridge, as shown in the figure,  it is given that resistance $$Y = 12.5\,\,\Omega $$ and that the balance is obtained at a distance $$39.5$$ $$cm$$ from end $$A$$ (by Jockey J). After interchanging the resistances $$X$$ and $$Y$$, a new balance point is found at a distance $${l_2}$$ from end $$A.$$ What are the value of $$X$$ and $${l_2}$$ ?

Accepted Answer

For balanced meter bridge,
$${X \over {39.5}}$$ = $${Y \over {\left( {100 - 39.5} ight)}}$$
$$ \Rightarrow $$$$\,\,\,\,$$  X = $${{12.5 	imes 39.5} \over {60.5}}$$
= 8.16 $$\Omega $$
Now, when we interchange X and Y then
$${Y \over {{l_2}}} = {X \over {100 - {l_2}}}$$
$$ \Rightarrow $$ $${{12.5} \over {{l_2}}} = {{8.16} \over {100 - {l_2}}}$$
$$ \Rightarrow $$20.66 $${{l_2}}$$ = 1250
$$ \Rightarrow $$ $${{l_2}}$$ = 60.5 $$\Omega $$

Answer

$$8.16\,\,\Omega $$ and $$60.5$$ $$cm$$

Answer

$$19.15\,\,\Omega $$ and $$39.5$$ $$cm$$

Answer

$$8.16\,\,\Omega $$ and $$39.5$$ $$cm$$

Answer

$$19.15\,\,\Omega $$ and $$60.5$$ $$cm$$

Current Electricity

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