Question 99: Current Electricity

Question

Two cells are connected in opposition as shown. Cell $$\mathrm{E}_1$$ is of $$8 \mathrm{~V}$$ emf and $$2 \Omega$$ internal resistance; the cell $$\mathrm{E}_2$$ is of $$2 \mathrm{~V}$$ emf and $$4 \Omega$$ internal resistance. The terminal potential difference of cell $$\mathrm{E}_2$$ is __________ V.

Accepted Answer

$$I=\frac{8-2}{2+4}=\frac{6}{6}=1 \mathrm{~A}$$
Applying Kirchhoff from C to B
$$\begin{aligned}
& V_C-2-4 	imes 1=V_B \\
& V_C-V_B=6 \mathrm{~V} \\
& =6 \mathrm{~V}
\end{aligned}$$

Current Electricity

Two cells are connected in opposition as shown. Cell $\mathrm{E}_1 is of 8 \mathrm{~V} emf and 2 \Omega internal resistance; the cell \mathrm{E}_2 is of 2 \mathrm{~V} emf and 4 \Omega internal resistance. The terminal potential difference of cell \mathrm{E}_2$ is __________ V.

Integer / Numeric Answer Type