Question 85: Centre of Mass and Rotational Motion

Question

As per the given figure, a small ball P slides down the quadrant of a circle and hits the other ball Q of equal mass which is initially at rest. Neglecting the effect of friction and assume the collision to be elastic, the velocity of ball Q after collision will be :
(g = 10 m/s
2
)

Accepted Answer

Mass is same and elastic collision, so speed gets exchanged, $$v=2$$ m/s

Answer

0.25 m/s

Answer

4 m/s

Answer

0

Answer

2 m/s

Centre of Mass and Rotational Motion

As per the given figure, a small ball P slides down the quadrant of a circle and hits the other ball Q of equal mass which is initially at rest. Neglecting the effect of friction and assume the collision to be elastic, the velocity of ball Q after collision will be : (g = 10 m/s 2 )

Choose the correct answer: