Question 86: Centre of Mass and Rotational Motion

Question

As per the given figure, a small ball P slides down the quadrant of a circle and hits the other ball Q of equal mass which is initially at rest. Neglecting the effect of friction and assume the collision to be elastic, the velocity of ball Q after collision will be :
(g = 10 m/s
2
)
![](https://app-content.cdn.examgoal.net/fly/@width/image/1ldre44mu/10470f3f-fd07-4543-8b62-71e206fb7023/ca0ae160-a554-11ed-803e-f1576252b48d/file-1ldre44mv.png?format=png)

Accepted Answer

Mass is same and elastic collision, so speed gets exchanged, $v=2$ m/s
![](https://app-content.cdn.examgoal.net/fly/@width/image/1lepw79yz/2ad5304d-47e6-4f48-b88c-84d28d7a6a00/2bff60b0-b84e-11ed-a412-5b325e9b0d2e/file-1lepw79z0.png?format=png)

Answer

0.25 m/s

Answer

4 m/s

Answer

0

Answer

2 m/s

Centre of Mass and Rotational Motion

As per the given figure, a small ball P slides down the quadrant of a circle and hits the other ball Q of equal mass which is initially at rest. Neglecting the effect of friction and assume the collision to be elastic, the velocity of ball Q after collision will be : (g = 10 m/s 2 )

Choose the correct answer: